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Classical Electromagnetic Fields Ir = N1 + 12: e-i«h-

Intuitively, we might expect that if this velocity is positive, the electron will decelerate, transferring energy to the field, while if the velocity is negative, the electron will accelerate, absorbing energy from the field. However as we know from the standard pendulum problem, the relative phase ~o with respect to the field also plays a crucial role. 130), we see that pz is negative if and only if sin K ~ is positive. Hence the electrons initially absorb energy for 0 :::; ~o :::; 7r / K and give up energy for 7r / K :::; ~o :::; 27r / K.

Classical Electromagnetic Fields o r Fig. 7. Second-order correlation function showing antibunching found in resonance fluorescence where we do not label the times, since we consider a stationary system with T = O. 100) g(2l(0) - 1 = (1\2 JdI P(I)(I - (1))2 . 101) Classically this must be positive, since (I - (1))2 ;::: 0 and the probability distribution P(I) must be positive. Hence g(2) cannot be less than unity, in contradiction to the experimental result shown in Fig. 7. At the beginning of this chapter we say that the fields we use can usually be treated classically.

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